^^ "I'm not exactly certain that 118 air temp and 98% relative humidity is possible.... The hotter the air gets the less capable it is of carrying moisture..."
The operative word is "relative," which is a ratio.
If air at a given temp
can only hold 1 gram of water vapor per cubic meter, but it's
really only holding 0.98 grams of water per cubic meter at that temp, that's 98% relative humidity: (0.98 grams ÷ 1.00 grams) X 100 = 98% Relative Humidity, R.H. or RH.
(That would be around minus 4°F, by the way,)
See:
http://www.engineeringtoolbox.com/maximum-moisture-content-air-d_1403.htmlAir at 104°F (40° C) can carry 51.1 grams of water (per m
3) as a vapor. If that cubic meter is only actually carrying 50.078 grams of water, that's 98% relative humidity.
If the air at that temperature is actually carrying the full 51.1 grams of water, it is "saturated," and is at the dew point for that temperature and is at 100% R.H. No further net evaporation can take place in "saturated" conditions. So your sweat won't evaporate and cool you off.
You will also note in that chart that the water-carrying capacity of air goes
up with temperature.
You might be thinking in terms of "live steam" or something, I don't know.
Incidentally, all the values cited are at a given standard pressure, usually 760mm of mercury, i.e., sea level air pressure.
Terry, 230RN
" 10
-3 kg/m
3 " in the table heading.
Note the table is headed 10
-3 kilograms per cubic meter. That's grams per cubic meter to the man in the street.
Edited for housekeeping, especially WRT the superscripting.